-[4z-(2z-2)]=5-(3z+4)

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Solution for -[4z-(2z-2)]=5-(3z+4) equation:


Simplifying
-1[4z + -1(2z + -2)] = 5 + -1(3z + 4)

Reorder the terms:
-1[4z + -1(-2 + 2z)] = 5 + -1(3z + 4)
-1[4z + (-2 * -1 + 2z * -1)] = 5 + -1(3z + 4)
-1[4z + (2 + -2z)] = 5 + -1(3z + 4)

Reorder the terms:
-1[2 + 4z + -2z] = 5 + -1(3z + 4)

Combine like terms: 4z + -2z = 2z
-1[2 + 2z] = 5 + -1(3z + 4)
[2 * -1 + 2z * -1] = 5 + -1(3z + 4)
[-2 + -2z] = 5 + -1(3z + 4)

Reorder the terms:
-2 + -2z = 5 + -1(4 + 3z)
-2 + -2z = 5 + (4 * -1 + 3z * -1)
-2 + -2z = 5 + (-4 + -3z)

Combine like terms: 5 + -4 = 1
-2 + -2z = 1 + -3z

Solving
-2 + -2z = 1 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
-2 + -2z + 3z = 1 + -3z + 3z

Combine like terms: -2z + 3z = 1z
-2 + 1z = 1 + -3z + 3z

Combine like terms: -3z + 3z = 0
-2 + 1z = 1 + 0
-2 + 1z = 1

Add '2' to each side of the equation.
-2 + 2 + 1z = 1 + 2

Combine like terms: -2 + 2 = 0
0 + 1z = 1 + 2
1z = 1 + 2

Combine like terms: 1 + 2 = 3
1z = 3

Divide each side by '1'.
z = 3

Simplifying
z = 3

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